Finy any day of any century Devcalendar

#include<iostream>
#include<conio.h>
using namespace std;
int main()
{
    long  int y,i,count=0,m,d,j;
      cout<<"Enter day-month-year.\n";
      cin>>d;cout<<"/";cin>>m;cout<<"/";cin>>y;
                  
       for (i=1;i<y;i++)
       {
            if ((i%400==0)||((i%4==0)&&(i%100!=0)))    //checking  leap year
            count= count+2;         
            else
            count=count+1;
       }
               
             for(j=1;j<m;j++)                 //checking  month
             {switch(j)
                     {case 1:case 3:case 5: case 7: case 8: case 10: case 12: count=count+31;break;  
                     case 2:if ((i%400==0)||((i%4==0)&&(i%100!=0))) count=count+29; else count=count+28;break;
                     default :count=count+30;
                     }
             }
                  count=count+d-1;
                  switch (count%7)
                  {
                  case 0:cout<<"Mon\n";break;
                  case 1:cout<<"Tues\n";break;
                  case 2:cout<<"Wed\n";break;
                  case 3:cout<<"Thu\n";break;
                  case 4:cout<<"Fri\n";break;
                  case 5:cout<<"Sat\n";break;
                  case 6:cout<<"Sun\n";break;
                 
                  }
                 
                  getch();
      }