Tuesday 4 December 2012

sum of series 1+x+(x^2)/2!+..............+(x^n)/n! c++ program

#include<iostream>
using namespace std;
#include<conio.h>

int fact(int);
#include<math.h>
int main()
{    double sum=1;
int x,i=1,n;
cout<<"1+x+(x^2)/2!+............+(x^n)/n!\n\n\n\n";
cout<<"enter the value of x    ";
cin>>x;
cout<<"enter th value of n      ";  cin>>n;
while(i<=n)
{
sum=sum+(pow(x,i)/fact (i));
i++;
}
double val=(double)sum;        //typecasting
cout<<"sum is "<<val;
getch();
}

int fact(int j)
{
int fact=1,k=1;
while(k<=j)
{
     fact=fact*k;
     k++;
     }
return fact;
}

No comments:

Post a Comment